What is the DNA template sequence that would produce the mRNA codon CGA during transcription?

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Multiple Choice

What is the DNA template sequence that would produce the mRNA codon CGA during transcription?

Explanation:
During transcription, the mRNA sequence is built to be complementary to the DNA template strand, with uracil replacing thymine. So to produce the mRNA codon CGA, the DNA template must have bases that pair with C, G, and A in that order: G pairs with C, C pairs with G, and T (DNA) pairs with A (RNA). This means the template DNA sequence is GCT (read in the 3'→5' direction so that the resulting mRNA is 5'→3' with CGA). Therefore, the DNA template sequence that would produce CGA is gct.

During transcription, the mRNA sequence is built to be complementary to the DNA template strand, with uracil replacing thymine. So to produce the mRNA codon CGA, the DNA template must have bases that pair with C, G, and A in that order: G pairs with C, C pairs with G, and T (DNA) pairs with A (RNA). This means the template DNA sequence is GCT (read in the 3'→5' direction so that the resulting mRNA is 5'→3' with CGA). Therefore, the DNA template sequence that would produce CGA is gct.

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